[kotlin] Optimisation: take less overridden symbols and check less expensive if there are none of them

`directlyOverriddenSymbols` is a sequence, no sense to call `.toList()` on it if we just need to check that it's empty

KTIJ-30819


(cherry picked from commit 598b8bf4654b4bdc7fd0a5e11c6b2ef9aec1aa00)

IJ-CR-148612

GitOrigin-RevId: 5a5b972145a95c37639c2f34d494bddb0011b595

plugins/kotlin/code-insight/inspections-k2/src/org/jetbrains/kotlin/idea/k2/codeinsight/inspections/UsePropertyAccessSyntaxInspection.kt

@@ -577,7 +577,7 @@ class UsePropertyAccessSyntaxInspection : LocalInspectionTool(), CleanupLocalIns
         val javaSymbols = allOverriddenSymbols.filter { it.origin.isJavaSourceOrLibrary() }.reversed()
         if (javaSymbols.isEmpty()) return false
         for (javaSymbol in javaSymbols) {
-            if (javaSymbol.allOverriddenSymbols.toList().isEmpty()) {
+            if (javaSymbol.directlyOverriddenSymbols.none()) {
                 // Nothing overrides it, true Java origin
                 return true
             }