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openide/plugins/javaFX/javaFX-CE/intellij.javaFX.community.iml
Nikolay Chashnikov f3805da91a [intellij project configuration] convert source roots without sources to resource roots
It should speed up compilation a little, and also makes it simpler to write tests which analyze class files in the module output (we can report an error if there are no class files in a module with source roots).

GitOrigin-RevId: 69ad9a23b1c4d7695e6d8715563d6630d3ae1a00
2023-03-10 14:51:42 +00:00

24 lines
1.5 KiB
XML

<?xml version="1.0" encoding="UTF-8"?>
<module type="JAVA_MODULE" version="4">
<component name="NewModuleRootManager" inherit-compiler-output="true">
<exclude-output />
<content url="file://$MODULE_DIR$">
<sourceFolder url="file://$MODULE_DIR$/testSrc" isTestSource="true" />
<sourceFolder url="file://$MODULE_DIR$/resources" type="java-resource" />
</content>
<orderEntry type="inheritedJdk" />
<orderEntry type="sourceFolder" forTests="false" />
<orderEntry type="module" module-name="intellij.javaFX" exported="" />
<orderEntry type="module" module-name="intellij.platform.ide.impl" scope="TEST" />
<orderEntry type="module" module-name="intellij.java.testFramework" scope="TEST" />
<orderEntry type="module" module-name="intellij.xml.impl" scope="TEST" />
<orderEntry type="module" module-name="intellij.groovy" scope="TEST" />
<orderEntry type="module" module-name="intellij.javaFX.common" scope="TEST" />
<orderEntry type="module" module-name="intellij.java.tests" scope="TEST" />
<orderEntry type="module" module-name="intellij.groovy.structuralSearch" scope="TEST" />
<orderEntry type="module" module-name="intellij.java.compiler" scope="TEST" />
<orderEntry type="module" module-name="intellij.platform.core.ui" />
<orderEntry type="module" module-name="intellij.javaFX.properties" scope="TEST" />
<orderEntry type="module" module-name="intellij.java.impl.refactorings" scope="TEST" />
</component>
</module>