lambda: simple inference in case of conditional expressions (IDEA-90812)

This commit is contained in:
Anna Kozlova
2012-09-03 19:21:59 +04:00
parent 73c9ab6718
commit 2996ce4b20
4 changed files with 64 additions and 3 deletions

View File

@@ -0,0 +1,39 @@
/*
* Copyright 2000-2012 JetBrains s.r.o.
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
class Test {
public interface I {
int m();
}
public interface I1 {
int m(int y);
}
{
boolean flag = true;
I i = flag ? (() -> 123) : (() -> 222);
I i1 = flag ? (<error descr="Missing return value">() -> {}</error>) : (() -> 222);
Object i2 = flag ? (<error descr="Target type of a lambda conversion must be an interface">() -> 42</error>) : (<error descr="Target type of a lambda conversion must be an interface">() -> 222</error>);
<error descr="Incompatible types. Found: '<lambda expression>', required: 'Test.I'">I i3 = flag ? ((x) -> 42) : (() -> 222);</error>
I i4 = flag ? (() -> 42) : new I() {
@Override
public int m() {
return 0; //To change body of implemented methods use File | Settings | File Templates.
}
};
}
}