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calc types by applicability constraints if inference fails

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include all inference variables for resolve and ignore additional constraints checks if the inference is going to failure; this way if (expr()) would get type of the 'standalone' expression instead of expression with boolean as expected type
This commit is contained in:
Anna.Kozlova
2017-12-07 13:06:24 +01:00
parent c9a3fba58c
commit 1fc76eb779
17 changed files with 69 additions and 66 deletions
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6
java/java-tests/testData/codeInsight/daemonCodeAnalyzer/lambda/highlighting/NoInferenceResult.java
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@@ -15,13 +15,13 @@ class NoInferenceResult {
<T> void m1(T t) { }
void test() {
m(<error descr="Object is not a functional interface">(String s1) -> (String s2) -> s1 + s2</error>);
m(<error descr="Object is not a functional interface">(String s1) -> {return (String s2) -> s1 + s2;}</error>);
m((String s1) -> <error descr="Target type of a lambda conversion must be an interface">(String s2) -> s1 + s2</error>);
m((String s1) -> {return <error descr="Target type of a lambda conversion must be an interface">(String s2) -> s1 + s2</error>;});
m((String s1) -> s1.length());
m((String s1) -> s1);
m1(<error descr="Object is not a functional interface">() -> { }</error>);
m1(<error descr="Target type of a lambda conversion must be an interface">() -> { }</error>);
Foo<String> foo = new Foo<String>();
foo.map(v -> null);